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Answer: A jet plane traveling 1890 km/h (525 m/s) pulls

Physics: Principles with Applications | 6th Edition | ISBN: 9780321569837 | Authors: Douglas C. Giancoli ISBN: 9780321569837 99

Solution for problem 2P Chapter 5

Physics: Principles with Applications | 6th Edition

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Physics: Principles with Applications | 6th Edition | ISBN: 9780321569837 | Authors: Douglas C. Giancoli

Physics: Principles with Applications | 6th Edition

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Problem 2P

A jet plane traveling 1890 km/h (525 m/s) pulls out of a dive by moving in an arc of radius 6.00 km. What is the plane’s acceleration in g’s?

Step-by-Step Solution:

Solution 2P

Step 1 of 3</p>

Here we have to calculate the acceleration of the plane in terms of acceleration due to gravity on Earth surface. The plane is performing circular motion, so here we need to calculate the centripetal acceleration.

Given data,

Linear speed of plane, Radius ,

Using                                  

Acceleration due to gravity,

To find,

Centripetal acceleration,

Step 2 of 3</p>

For an object performing uniform circular motion, the centripetal force acts on it. Due to which it has the centripetal acceleration acts on it and is given by the rate of change of tangential velocity as in figure below

When an object moves in a circle with uniform speed, it has a centripetal acceleration , directed toward the center. This centripetal acceleration is directed along a radius so it may also be called the radial acceleration.

The expression for the centripetal acceleration() ,

                                 =

 Where v are the linear velocity of the object and r is the radius.

Step 3 of 3

Chapter 5, Problem 2P is Solved
Textbook: Physics: Principles with Applications
Edition: 6
Author: Douglas C. Giancoli
ISBN: 9780321569837

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Answer: A jet plane traveling 1890 km/h (525 m/s) pulls

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