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swimmer shown in Figure 7.44 exerts an average horizontal

Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli ISBN: 9780130606204 3

Solution for problem 56PE Chapter 7

Physics: Principles with Applications | 6th Edition

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Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli

Physics: Principles with Applications | 6th Edition

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Problem 56PE

swimmer shown in Figure 7.44 exerts an average horizontal backward force of 80.0 N with his arm during each 1.80 m long stroke. (a) What is his work output in each stroke? (b) Calculate the power output of his arms if he does 120 strokes per minute.

Step-by-Step Solution:

Step-by-step solution Step 1 of 4 The formula to find the work is, Here is the work done, is the force and is the displacement in the direction of applied force. (a) The output work by a swimmer in each stroke who exerts an average horizontal backward force each stroke is Therefore, the output work by the swimmer in each stroke is . Step 2 of 4 (b) To calculate the power output of his arm if he does 120 strokes per minute, first find out the value of work per minute, Therefore, he consumes .

Step 3 of 4

Chapter 7, Problem 56PE is Solved
Step 4 of 4

Textbook: Physics: Principles with Applications
Edition: 6
Author: Douglas C. Giancoli
ISBN: 9780130606204

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swimmer shown in Figure 7.44 exerts an average horizontal

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