IP BIO A cheetah can accelerate from rest to 25.0 m/s in | StudySoup

Textbook Solutions for Physics with MasteringPhysics

Chapter 2 Problem 48P

Question

A cheetah can accelerate from rest to 25.0 m/s in 6.22 s. Assuming constant acceleration, (a) how far has the cheetah run in this time? (b) After sprinting for just 3.13 s, is the cheetah's speed 12.5 m/s, more than 12.5 m/s, or less than 12.5 m/s? Explain, (c) What is the cheetah's average speed for the first 3.11 s of its sprint? For the second 3.11 s of its sprint? (d) Calculate the distance covered by the cheetah in the first 3.11 s and the second 3.11 s.

Solution

Step 1 of 7

Given data:

A cheetah can accelerate from rest, which is the initial speed, to 25.0 m/s, the final speed in 6.22 s, the time duration.

Step 2 of 7

(a)

The acceleration of the motion of the cheetah is calculated as follows.

The acceleration can be determined as,

\(a = \frac{{{v_f} - {v_i}}}{t}\)  …… (1)

In the above equation, \({v_i}\) is the initial speed, \({v_f}\) is the final speed, a is the acceleration of the body, and t is a time interval.

The relation for distance traveled in the given time is

\(\Delta x = \frac{{{v^2} - {u^2}}}{{2a}}\)  …… (2)

The relation for the average speed of the motion is

\({v_{av}} = \frac{{{v_i} + {v_f}}}{2}\)  …… (3)

The relation for final speed is

\({v_f} = {v_i} + at\)  …… (4)

Substitute the values in equation 1, and we get,

\(a = \frac{{25}}{{6.22}}\)

\(a = 4.02\;{\rm{m/}}{{\rm{s}}^2}\)

The distance covered by the cheetah

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full solution

Title Physics with MasteringPhysics 4 
Author James S. Walker
ISBN 9780321541635

IP BIO A cheetah can accelerate from rest to 25.0 m/s in

Chapter 2 textbook questions

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