IP Referring to Example 19?6 The magnitude of the charge | StudySoup

Textbook Solutions for Physics with MasteringPhysics

Chapter 19 Problem 109IP

Question

Referring to Example 19–6 The magnitude of the charge is changed until the angle the thread makes with the vertical is \(\theta=15^{\circ}\). The electric field is \(1.46 X 10^{4} \mathrm{~N} / \mathrm{C}\) and the mass of the object is 0.0250 kg.

(a) Is the new magnitude of q greater than or less than its previous value? Explain.

(b) Find the new value of q.

Solution

Step 1 of 3

(a)

Here we need to explain whether the new magnitude of the charge  is greater or lesser than the previous value. In the given case, the magnitude of charge is changed until the thread makes an angle with vertical axis. The electric field and mass of the object are given to be  and .

Comparing to the previous case, the angle  is increased from  to . The electrostatic force which is equal to  increases in magnitude. Since the magnitude of electric field is same in both the cases, the magnitude of the charge must be increased compared to previous case, in order to have greater force.

Therefore, the new magnitude of the charge  is greater than the previous value.

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Title Physics with MasteringPhysics 4 
Author James S. Walker
ISBN 9780321541635

IP Referring to Example 19?6 The magnitude of the charge

Chapter 19 textbook questions

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