A bullet of mass embeds itself in a wooden block with mass
Chapter 7, Problem 43(choose chapter or problem)
(III) A bullet of mass \(m=0.0010\) kg embeds itself in a wooden block with mass \(M=0.999\) kg which then compresses a spring \((k=140~ \mathrm{N/m})\) by a distance \(x=0.050~ \mathrm m\) before coming to rest. The coefficient of kinetic friction between the block and table is \(\mu=0.50\).
\((a)\) What is the initial velocity (assumed horizontal) of the bullet?
\((b)\) What fraction of the bullet’s initial kinetic energy is dissipated (in damage to the wooden block, rising temperature, etc.) in the collision between the bullet and the block?
Equation Transcription:
Text Transcription:
m=0.0010 kg
M=0.999 kg
(k=140 N/m)
x=0.050 m
mu=0.50
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