Physics / Physics: Principles with Applications 7 / Chapter 19 / Problem 78

Physics: Principles with Applications | 7th Edition | ISBN: 9780321625922 | Authors: Douglas C. Giancoli

The current through the resistor in Fig. 1977 is 3.10 mA.

Chapter 19, Problem 78

(choose chapter or problem)

The current through the 4.0-k$\Omega$ resistor in Fig. 19–77 is 3.10 mA. What is the terminal voltage $V_\mathrm{ba}$ of the “unknown” battery? (There are two answers. Why?)

Equation Transcription:

$4.0-k\Omega{}$

${V}_{ba}$

$3.2\ k\Omega{}$

$1.0\ k\Omega{}$

$8.0\ k\Omega{}$

$4.0\ k\Omega{}$

Text Transcription:

4.0-k Omega

V_ba

3.2 k Omega

1.0 k Omega

8.0 k Omega

4.0 k Omega

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The current through the resistor in Fig. 1977 is 3.10 mA.

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