Two people of equal mass attempt a tug-of-war with a 12-m rope while standing on frictionless ice. When they pull on the rope, each of them slides toward the other. How do their accelerations compare, and how far does each person slide before they meet?
Solution Step 1 of 2 In tug-of-war, each person at two ends having same mass, will pull the rope with same force. Since they have equal masses and the apply same force at each end of the rope. By Newton's second law, F=ma Mass is same, Fa As Force is same at two ends, So they will have the equal acceleration and hence they will be having same speed.