What is the acceleration of the stone of Exercise 1 at the top of its path? Exercise 1–2 1. Suppose the string in the exercise 2 breaks and the stone slows in its upward motion. Draw a force vector diagram of the stone when it reaches the top of its path. 2. Here the same stone is being accelerated vertically upward. (a) Draw force vectors to some suitable scale showing relative forces acting on the stone. (b) Which is the longer vector, and why?
Solution 47E Step 1; When the string of the rock is broken, its velocity becomes zero, hence the acceleration vertically upward also becomes acceleration Thus the acceleration at the top of its path will be the acceleration due to gravity which is given by g = 9.8 m/s pointed downwards