Answer: Two forces act on the screw eye. If F1 = 400 N and

Chapter 2, Problem 2-23

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QUESTION:

Two forces act on the screw eye. If \(F_1 = 400\ N\) and \(F_2 = 600\ N\0, determine the angle \(\theta (0^{\circ}\ \leq\ \theta\ \leq\ 180^{\circ})\) between them, so that the resultant force has a magnitude of \(F_R = 800\ N\).

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QUESTION:

Two forces act on the screw eye. If \(F_1 = 400\ N\) and \(F_2 = 600\ N\0, determine the angle \(\theta (0^{\circ}\ \leq\ \theta\ \leq\ 180^{\circ})\) between them, so that the resultant force has a magnitude of \(F_R = 800\ N\).

ANSWER:

Step 1 of 3

The angle  can be solved using the triangle law. Construct a triangle as shown below.

Connect the tail of  force to the head of  force. Note that components are in tail-head connection while component and resultant are either tail-tail or head-head connections.

Step  2 of 3

To solve for the angle

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