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Answer: Two forces act on the screw eye. If F1 = 400 N and
Chapter 2, Problem 2-23(choose chapter or problem)
Two forces act on the screw eye. If \(F_1 = 400\ N\) and \(F_2 = 600\ N\0, determine the angle \(\theta (0^{\circ}\ \leq\ \theta\ \leq\ 180^{\circ})\) between them, so that the resultant force has a magnitude of \(F_R = 800\ N\).
Questions & Answers
QUESTION:
Two forces act on the screw eye. If \(F_1 = 400\ N\) and \(F_2 = 600\ N\0, determine the angle \(\theta (0^{\circ}\ \leq\ \theta\ \leq\ 180^{\circ})\) between them, so that the resultant force has a magnitude of \(F_R = 800\ N\).
ANSWER:
Step 1 of 3
The angle can be solved using the triangle law. Construct a triangle as shown below.
Connect the tail of force to the head of force. Note that components are in tail-head connection while component and resultant are either tail-tail or head-head connections.
Step 2 of 3
To solve for the angle