An archer shoots an arrow at a 75.0 m distant target; the | StudySoup

Textbook Solutions for College Physics

Chapter 3 Problem 29

Question

Problem 29PE

An archer shoots an arrow at a 75.0 m distant target; the bull’s-eye of the target is at same height as the release height of the arrow. (a) At what angle must the arrow be released to hit the bull’s-eye if its initial speed is 35.0 m/s? In this part of the problem, explicitly show how you follow the steps involved in solving projectile motion problems. (b) There is a large tree halfway between the archer and the target with an overhanging horizontal branch 3.50 m above the release height of the arrow. Will the arrow go over or under the branch?

Solution

Solution 29PE

Step 1 of 6

An arrow is released at an angle  with a speed  towards a bull’s eye which is at the same height as the release height of arrow and at a horizontal distance R=75 m from the arrow release position. Here we need to calculate the angle    at which the arrow has to be released, so that it hits the bull’s eye. In the second part we have to find, at the half way between the release point and the target is the arrow is moving above or below a branch of height 3.5m.

Subscribe to view the
full solution

Title College Physics  1 
Author Paul Peter Urone, Roger Hinrichs
ISBN 9781938168000

An archer shoots an arrow at a 75.0 m distant target; the

Chapter 3 textbook questions

×

Login

Organize all study tools for free

Or continue with
×

Register

Sign up for access to all content on our site!

Or continue with

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back