Derive for the range of a projectile on level ground by | StudySoup

Textbook Solutions for College Physics

Chapter 3 Problem 49

Question

Derive \(R=\frac{v_{0}^{2} \sin 2 \theta_{0}}{g}\) for the range of a projectile on level ground by finding the time \(t\) at which \(y\) becomes zero and substituting this value of \(t\) into the expression for \(x-x_{0}\), noting that \(R=x-x_{0}\)

Solution

Step 1 of 7:

        The range of the projectile is the horizontal distance traveled by the projectile from the point of launch and the point where the vertical height becomes zero or it hits the ground. We are going to derive the equation of the horizontal range of the projectile. This process has two steps, they are finding the time of flight of the projectile and with the time of flight, we can able to find the range.

        

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Title College Physics  1 
Author Paul Peter Urone, Roger Hinrichs
ISBN 9781938168000

Derive for the range of a projectile on level ground by

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