Solution Found!
The Downtown Parking Authority of Tampa, Florida, reported
Chapter 6, Problem 8E(choose chapter or problem)
The Downtown Parking Authority of Tampa, Florida, reported the following information for a sample of 250 customers on the number of hours cars are parked and the amount they are charged.
\(\begin{array}{|ccc|} \hline \text { Number of Hours } & \text { Frequency } & \text { Amount Charged } \\ \hline 1 & 20 & \$ 3.00 \\ 2 & 38 & 6.00 \\ 3 & 53 & 9.00 \\ 4 & 45 & 12.00 \\ 5 & 40 & 14.00 \\ 6 & 13 & 16.00 \\ 7 & 5 & 18.00 \\ 8 & 36 & 20.00 \\ & \overline {250} & \\ \hline \end{array}\)
a. Convert the information on the number of hours parked to a probability distribution. Is this a discrete or a continuous probability distribution?
b. Find the mean and the standard deviation of the number of hours parked. How would you answer the question: How long is a typical customer parked?
c. Find the mean and the standard deviation of the amount charged.
Questions & Answers
QUESTION:
The Downtown Parking Authority of Tampa, Florida, reported the following information for a sample of 250 customers on the number of hours cars are parked and the amount they are charged.
\(\begin{array}{|ccc|} \hline \text { Number of Hours } & \text { Frequency } & \text { Amount Charged } \\ \hline 1 & 20 & \$ 3.00 \\ 2 & 38 & 6.00 \\ 3 & 53 & 9.00 \\ 4 & 45 & 12.00 \\ 5 & 40 & 14.00 \\ 6 & 13 & 16.00 \\ 7 & 5 & 18.00 \\ 8 & 36 & 20.00 \\ & \overline {250} & \\ \hline \end{array}\)
a. Convert the information on the number of hours parked to a probability distribution. Is this a discrete or a continuous probability distribution?
b. Find the mean and the standard deviation of the number of hours parked. How would you answer the question: How long is a typical customer parked?
c. Find the mean and the standard deviation of the amount charged.
ANSWER:Step 1 of 4
Given data:
The known frequency distribution for the number of hours cars are parked, and the amount charged is,
\(\begin{array}{|ccc|} \hline \text { Number of Hours } & \text { Frequency } & \text { Amount Charged } \\ \hline 1 & 20 & \$ 3.00 \\ 2 & 38 & 6.00 \\ 3 & 53 & 9.00 \\ 4 & 45 & 12.00 \\ 5 & 40 & 14.00 \\ 6 & 13 & 16.00 \\ 7 & 5 & 18.00 \\ 8 & 36 & 20.00 \\ & \overline {250} & \\ \hline \end{array}\)