In a Poisson distribution µ = 4.a. What is the probability | StudySoup

Textbook Solutions for Basic Statistics for Business and Economics

Chapter 6 Problem 26E

Question

In a Poisson distribution \(\mu=4\).

a. What is the probability that x = 2?

b. What is the probability that \(x \leq 2\)?

c. What is the probability that x > 2?

Solution

Step 1 of 3

(a) We are asked to find the probability that x = 0

Given that Poisson distribution with mean \(\mu=4\)

The probability mass function (PMF) of Poisson distribution is

\(\begin{array}{l}
P(X=x)=\frac{e^{-\mu} \mu^{x}}{x !}\\
\begin{aligned}
P(X & =2)=\frac{e^{-4}(4)^{2}}{2 !} \\
& =0.1465
\end{aligned}
\end{array}\)

Hence the probability of x = 0 is 0.1465

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full solution

Title Basic Statistics for Business and Economics  7 
Author Douglas Lind; William Marchal; Samuel Wathen
ISBN 9780077384470

In a Poisson distribution µ = 4.a. What is the probability

Chapter 6 textbook questions

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