A ball is attached to a horizontal cord of length whose other end is fixed (Fig. ). If the ball is released, what will be its speed at the lowest point of its path? (b) A peg is located a distance directly below the point of attachment of the cord. If what will be the speed of the ball when it reaches the top of its circular path about the peg?
Step 1 of 2
The potential energy of the ball at its initial position = mgL.
Its speed at the lowest point of its path is given from the principle of conservation
of energy as:
We put v on the left side of the equation and everything else on the right side and we take square root of both sides and we get: