A ball is attached to a horizontal cord of length whose other end is fixed, Fig. 6-49. (a) If the ball is released, what will be its speed at the lowest point of its path? (i>)A peg is located a distance h directly below the point of attachment of the cord. If h = 0.801, what will be the speed of the ball when it reaches the top of its circular path about the peg?
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The potential energy of the ball at its initial position = mgL.
Its speed at the lowest point of its path is given from the principle of conservation
of energy as:
We put v on the left side of the equation and everything else on the right side and we take square root of both sides and we get: