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A woman swimming upstream is not moving with respect to

Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli ISBN: 9780130606204 3

Solution for problem 4Q Chapter 6

Physics: Principles with Applications | 6th Edition

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Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli

Physics: Principles with Applications | 6th Edition

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Problem 4Q

Problem 4Q

A woman swimming upstream is not moving with respect to the shore. Is she doing any work? If she stops swimming and merely floats, is work done on her?

Step-by-Step Solution:
Step 1 of 3

Chapter 2: Motion in One Dimension 2.1 Describing Motion distance = scalar , displacement = vector = Δx (orΔy ) ‘trajectory’ When she goes Position vs time x vs t): slope = velocity backwards, the slope and velocity are negative. speed = scalar , velocity = vector v = Δx v = Δy x Δt y Δt 2.2 Uniform Motion constant velocity ! no speed-up or slow-down AND no change in direction!! € € Δx = v xt , or x – x0= v xt – t 0 , which we usually write as x = vxt , taking initial time and position

Step 2 of 3

Chapter 6, Problem 4Q is Solved
Step 3 of 3

Textbook: Physics: Principles with Applications
Edition: 6
Author: Douglas C. Giancoli
ISBN: 9780130606204

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A woman swimming upstream is not moving with respect to