What is the instantaneous velocity of a freely falling object 10 s after it is released from a position of rest? What is its average velocity during this 10-s interval? How far will it fall during this time?
Answers: Step 1: Here ,we have calculate Instantaneous velocity= Average velocity = Total distance travelled= Given: Time = 10 seconds Acceleration due to gravity = 9.8 m/s ( as the object is falling from a certain) initial velocity(u) = 0 Step 2: We know the three equations of motion. V= u + at………….(1) 2 S= ut +½ at ……..(2) V = u + 2as ……..(3) Here = V is the final velocity u is the initial velocity S is the displacement t is the time taken a is acceleration or acceleration due to gravity (g) Step 3: To calculate instantaneous velocity, we can use equation (1) of motion as above, Substituting value of g or a = 9.8 m/s and initial velocity(object at rest) (u) = 0 V = u + at …………..(1) 2 There V= 0 + 9.8 m/s x 10s V= 98 m/s Therefore the instantaneous velocity of the falling object 98 m/s,
Textbook: Conceptual Physics
Author: Paul G. Hewitt
This full solution covers the following key subjects: velocity, during, interval, falling, far. This expansive textbook survival guide covers 45 chapters, and 4650 solutions. Since the solution to 3P from 3 chapter was answered, more than 327 students have viewed the full step-by-step answer. Conceptual Physics was written by and is associated to the ISBN: 9780321909107. The answer to “What is the instantaneous velocity of a freely falling object 10 s after it is released from a position of rest? What is its average velocity during this 10-s interval? How far will it fall during this time?” is broken down into a number of easy to follow steps, and 38 words. The full step-by-step solution to problem: 3P from chapter: 3 was answered by , our top Physics solution expert on 04/03/17, 08:01AM. This textbook survival guide was created for the textbook: Conceptual Physics, edition: 12.