Surprisingly, very few athletes can jump more than 2 feet (0.6 m) straight up. Use d = 1/2?gt?2 and solve for the time one spends moving upward in a 0.6-m vertical jump. Then double it for the “hang time”—the time one’s feet are off the ground.

ANSWER: STEP 1:- We know the equation of motion, 2 d = 1/2 at ----------------(1) Where, d is the total distance travelled, u is the initial velocity, 2 a is the acceleration and for this case a = g = 9.8 m/s , t is the time interval. STEP 2:- According to the question, the person covered a distance of 0.6 meters. The acceleration value we know already, a = 9.8 m/s . So, let’s put the values in equation (1), 0.6 m = 1/2 × 9.8 × t t = (0.6 × 2) / 9.8 = 0.122 t = 0.122 = 0.349 s. This is the time required to reach the height of 0.6 meters. The total time with the feet above the ground is, 2 × t = 2 × 0.349...