You push your physics book 1.50 m along a horizontal table-top with a horizontal push of 2.40 N while the opposing force of friction is 0.600 N. How much work does each of the following forces do on the book: (a) your 2.40-N push, (b) the friction force, (c) the normal force from the tabletop, and (d) gravity? (e) What is the net work done on the book?

Solution 1E Introduction Here force and displacement is given, and we can also find out the angle between the force and the displacement. So we can calculate the work for each case. Solution The work is given by W = F ยท d = Fdcos Here F and d are the magnitude of force and displacement. (a) The book will move in the direction of the applied force, if the force is horizontal then the angle between force and displacement is = 0 rad. Hence the work is given by W = Fdcos = (2.40 N)(1.50 m)cos0 = 3.60 J 1 (b) Friction always opposes the motion, that is the direction of the frictional force and the displacement will be opposite to each other, which means the angle between the frictional force and the displacement is rad....