×
Log in to StudySoup
Get Full Access to Physics - Textbook Survival Guide
Join StudySoup for FREE
Get Full Access to Physics - Textbook Survival Guide

A little red wagon with mass 7.00 kg moves in a straight

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 27E Chapter 6

University Physics | 13th Edition

  • Textbook Solutions
  • 2901 Step-by-step solutions solved by professors and subject experts
  • Get 24/7 help from StudySoup virtual teaching assistants
University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

4 5 0 255 Reviews
26
2
Problem 27E

A little red wagon with mass 7.00 kg moves in a straight line on a frictionless horizontal surface. It has an initial speed of 4.00 m/s and then is pushed 3.0 m in the direction of the initial velocity by a force with a magnitude of 10.0 N. (a) Use the work–energy theorem to calculate the wagon’s final speed. (b) Calculate the acceleration produced by the force. Use this acceleration in the kinematic relationships of Chapter 2 to calculate the wagon’s final speed. Compare this result to that calculated in part (a).

Step-by-Step Solution:

Solution 27E Step 1: Data given Mass m = 7.00 kg Initial velocity vi= 4.00 m/s Distance travelled x = 3.00 m Force exerted F = 10.0 N We need to find the final speed of wagon wheel Let us find the work done The work done by the applied force over the 3.00 m distance It is obtained using W = Fx Substituting the values we get W = 10.0 N × 3.00 m W = 30.0 J Thus we have work done = 30.0 J As per the work energy relations We can write 2 2 W = 1/2 mv 1i2 mv f Substituting we get 2 2 30 J = 1/2 × 7.0 kg × (4 m/s) 1/2 × 7.0 kg × v f Rearranging and solving we get 2 v = 2(30J)+7.00 kg ×(4 m/s) 7.00 kg 2((30J)+7.00 kg ×(4 m/s) ) v = 7.00 kg v = 4.96 m/s Step 2: We need to find the acceleration produced by the force We know F = m × a Since we need to find acceleration We shall rearrange to get a = F/m Substituting values we get a = 10.0 N /7 kg 2 a = 1.43 m/s Thus we have acceleration as 1.43 m/s 2

Step 3 of 3

Chapter 6, Problem 27E is Solved
Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

Unlock Textbook Solution

Enter your email below to unlock your verified solution to:

A little red wagon with mass 7.00 kg moves in a straight

×
Log in to StudySoup
Get Full Access to Physics - Textbook Survival Guide
Join StudySoup for FREE
Get Full Access to Physics - Textbook Survival Guide
×
Reset your password