CALC? A net force along the x -axis that has x- component Fx = -12.0 N + (0.300 N/m2)x2 is applied to a 5.00-kg object that is initially at the origin and moving in the -x-direction with a speed of 6.00 m/s. What is the speed of the object when it reaches the point x = 5.00 m?

Solution 70P Step 1: Provided, F(x) = -12.0 N + (0.300 N/m )x 2 2 Initial speed of the object, u = 6.00 m/s Distance it moved, x = 5.00 m Force required to move from origin to x = 5.00 m 2 2 2 2 F = - 12.0 N + (0.300 N/m ) 5 m /s F = - 12.0 N + 7.5 N = - 4.5 N Work done to move 5 m is, W = Fx W = - 4.5 N × 5 m = - 22.5 J