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In a Little League baseball game, team A’s pitcher throws

Probability and Statistics for Engineers and the Scientists | 9th Edition | ISBN: 9780321629111 | Authors: Ronald E. Walpole; Raymond H. Myers; Sharon L. Myers; Keying E. Ye ISBN: 9780321629111 32

Solution for problem 108E Chapter 2

Probability and Statistics for Engineers and the Scientists | 9th Edition

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Probability and Statistics for Engineers and the Scientists | 9th Edition | ISBN: 9780321629111 | Authors: Ronald E. Walpole; Raymond H. Myers; Sharon L. Myers; Keying E. Ye

Probability and Statistics for Engineers and the Scientists | 9th Edition

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Problem 108E

In a Little League baseball game, team A’s pitcher throws a strike 50% of the time and a ball 50% of the time, successive pitches are independent of one another, and the pitcher never hits a batter. Knowing this, team B’s manager has instructed the first batter not to swing at anything. Calculate the probability that a. The batter walks on the fourth pitch b. The batter walks on the sixth pitch (so two of the first five must be strikes), using a counting argument or constructing a tree diagram c. The batter walks d. The first batter up scores while no one is out (assuming that each batter pursues a no-swing strategy)

Step-by-Step Solution:

Solution : Step 1: It is given that in a Little League baseball game, team A’s pitcher throws a strike 50% of the time and a ball 50% of the time. Also given that successive pitches are independent of one another, and the pitcher never hits a batter. The team B manager instructed to the first batter not swing at anything. Step 2 : a) We have to find the probability that the batter walks on 4th pitch. Since it is given that a pitcher throws a strike 50% of the time and a ball 50% of the time. So there is an equal chances for both. Means probability of a pitcher throws a strike = probability that a batter throws a ball = 0.50= ½ So The P( the batter walks on the 4th pitch)= (½)^4 = .0625 b) we have to find the probability that the batter walks on the sixth pitch. Which means two of the first five must be strikes. P( the batter walks on the 6th pitch)=P((3 balls, 2 strike)+ball) Since the successive pitches are independent =P( 3 balls, 2 strikes)× P(ball) = 5 choose 2 × (½)^5 × (½) 5 = C2 × (½)^5 ×(½) = 10×(1/64) = 0.15625

Step 3 of 4

Chapter 2, Problem 108E is Solved
Step 4 of 4

Textbook: Probability and Statistics for Engineers and the Scientists
Edition: 9
Author: Ronald E. Walpole; Raymond H. Myers; Sharon L. Myers; Keying E. Ye
ISBN: 9780321629111

This full solution covers the following key subjects: batter, walks, swing, team, pitcher. This expansive textbook survival guide covers 18 chapters, and 1582 solutions. Since the solution to 108E from 2 chapter was answered, more than 367 students have viewed the full step-by-step answer. The answer to “In a Little League baseball game, team A’s pitcher throws a strike 50% of the time and a ball 50% of the time, successive pitches are independent of one another, and the pitcher never hits a batter. Knowing this, team B’s manager has instructed the first batter not to swing at anything. Calculate the probability that a. The batter walks on the fourth pitch b. The batter walks on the sixth pitch (so two of the first five must be strikes), using a counting argument or constructing a tree diagram c. The batter walks d. The first batter up scores while no one is out (assuming that each batter pursues a no-swing strategy)” is broken down into a number of easy to follow steps, and 113 words. Probability and Statistics for Engineers and the Scientists was written by and is associated to the ISBN: 9780321629111. This textbook survival guide was created for the textbook: Probability and Statistics for Engineers and the Scientists, edition: 9. The full step-by-step solution to problem: 108E from chapter: 2 was answered by , our top Statistics solution expert on 05/06/17, 06:21PM.

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