Solution Found!
(Note: In Problems, assume a number like 6.4 is
Chapter 2, Problem 16P(choose chapter or problem)
(Note: In Problems, assume a number like 6.4 is accurate to \(\pm 0.1\); and 950 is \(\pm 10\) unless 950 is said to be “precisely” or “very nearly” 950, in which case assume \(950 \pm 1\). See Section 1–4.)
(III) An automobile traveling \(\text {95 km/h}\) overtakes a 1.30-kmlong train traveling in the same direction on a track parallel to the road. If the train’s speed is \(\text {75 km/h}\), how long does it take the car to pass it, and how far will the car have traveled in this time? See Fig. 2–36. What are the results if the car and train are traveling in opposite directions?
Equation Transcription:
Text Transcription:
+/-0.1
+/-10
95+/-01
95 km/h
75 km/h
v=75 km/h
v=95 km/h
Questions & Answers
QUESTION:
(Note: In Problems, assume a number like 6.4 is accurate to \(\pm 0.1\); and 950 is \(\pm 10\) unless 950 is said to be “precisely” or “very nearly” 950, in which case assume \(950 \pm 1\). See Section 1–4.)
(III) An automobile traveling \(\text {95 km/h}\) overtakes a 1.30-kmlong train traveling in the same direction on a track parallel to the road. If the train’s speed is \(\text {75 km/h}\), how long does it take the car to pass it, and how far will the car have traveled in this time? See Fig. 2–36. What are the results if the car and train are traveling in opposite directions?
Equation Transcription:
Text Transcription:
+/-0.1
+/-10
95+/-01
95 km/h
75 km/h
v=75 km/h
v=95 km/h
ANSWER:
Step 1 of 4
Given data,
Length of the train is :
Speed of the automobile:
Speed of the train is
Assume that the train travels a distance of “x” kilometers in 
. 