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A uniform bar has two small balls glued to its ends. The

Chapter 11, Problem 30E

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QUESTION:

A uniform bar has two small balls glued to its ends. The bar is 2.00 m long and has mass 4.00 kg, while the balls each have mass 0.300 kg and can be treated as point masses. Find the moment of inertia of this combination about an axis (a) perpendicular to the bar through its center; (b) perpendicular to the bar through one of the balls; (c) parallel to the bar through both balls; and (d) parallel to the bar and 0.500 m from it.

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QUESTION:

A uniform bar has two small balls glued to its ends. The bar is 2.00 m long and has mass 4.00 kg, while the balls each have mass 0.300 kg and can be treated as point masses. Find the moment of inertia of this combination about an axis (a) perpendicular to the bar through its center; (b) perpendicular to the bar through one of the balls; (c) parallel to the bar through both balls; and (d) parallel to the bar and 0.500 m from it.

ANSWER:

Solution 30E Step 1: Moment of inertia of a uniform rod having mass M and length L rotating with an axis passing through its center is, Irod= 1/12 ML 2 Here, M = 4 kg and L = 2 m Then, I = 1/12 × 4 kg × 2 m = 4/3 kg m 2 rod

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