The flywheel of a gasoline engine is required to give up 500 J of kinetic energy while its angular velocity decreases from 650 rev/min to 520 rev/min. What moment of inertia is required?
Solution 43E Step 1 of 4: In the given problem, we need to calculate the moment of inertia(I) required to change the Kinetic energy of the skywheel by KE =500 J by reducing the angular speed from = 650 i rev/min to =f500 rev/min. Given data, Change in kinetic energy, KE =500 J Initial angular speed, =i650 rev/min Final speed, = f00 rev/min To find, Initial kinetic energy, KE = i Final kinetic energy, KE =f Moment of inertia, I= Step 2 of 4 To convert angular speed from rev/min to rad/sec Using 1 rev = 2 rad and 1 min= 60 sec For = 650 rev/min = 650 ×2 rad/sec i i 60 = 68.03 rad/sec i 520 ×2 For =f520 rev/min f 60 rad/sec f 54.42 rad/sec
Textbook: University Physics
Author: Hugh D. Young, Roger A. Freedman
The answer to “The flywheel of a gasoline engine is required to give up 500 J of kinetic energy while its angular velocity decreases from 650 rev/min to 520 rev/min. What moment of inertia is required?” is broken down into a number of easy to follow steps, and 33 words. This full solution covers the following key subjects: min, rev, required, its, flywheel. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. Since the solution to 43E from 9 chapter was answered, more than 817 students have viewed the full step-by-step answer. University Physics was written by and is associated to the ISBN: 9780321675460. This textbook survival guide was created for the textbook: University Physics, edition: 13. The full step-by-step solution to problem: 43E from chapter: 9 was answered by , our top Physics solution expert on 05/06/17, 06:07PM.