Three pieces of string, each of length L, are joined | StudySoup

Textbook Solutions for University Physics

Chapter 15 Problem 53P

Question

Three pieces of string, each of length L, are joined together end to end, to make a combined string of length 3 L. The first piece of string has mass per unit length µ1, the second piece has mass per unit length µ2 = 4µ1, and the third piece has mass per unit length µ3 = µ1/4. (a) If the combined string is under tension F, how much time does it take a transverse wave to travel the entire length 3L? Give your answer in terms of L, F, and µ1. (b) Does your answer to part (a) depend on the order in which the three pieces are joined together? Explain.

Solution

Solution 53P Step 1 of 4: (a) If the combined string is under tension F, how much time does it take a transverse wave to travel the entire length 3L Give your answer in terms of L, F, and µ1. Tension(F) and length(L) is same on for all the strings, but the mass per unit length varies. As the speed of the transverse wave depends on the mass per unit length, the speed is different on different strings. Therefore, time taken to cover the equal distance on the equal length string will be different. In order to calculate the total time taken to travel 3L distance, we need to first calculate the speeds. Given data Mass per unit length of 1st string,1 Mass per unit length of 2st string,2 = 41 Mass per unit length of 1st string,3 =41 To find Time taken to travel 3L distance, t=

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full solution

Title University Physics 13 
Author Hugh D. Young, Roger A. Freedman
ISBN 9780321675460

Three pieces of string, each of length L, are joined

Chapter 15 textbook questions

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