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Get Full Access to University Physics - 13 Edition - Chapter 15 - Problem 66p
Get Full Access to University Physics - 13 Edition - Chapter 15 - Problem 66p

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# CP A vertical, 1.20-m length of 18-gauge (diameter of

ISBN: 9780321675460 31

## Solution for problem 66P Chapter 15

University Physics | 13th Edition

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Problem 66P

CP ?A vertical, 1.20-m length of 18-gauge (diameter of 1.024 mm) copper wire has a 100.0-N ball hanging from it. (a) What is the wavelength of the third harmonic for this wire? (b) A 500.0-N ball now ?replaces ?the original ball. What is the change in the wavelength of the third harmonic caused by replacing the light ball with the heavy one? (?Hint: ?See Table 11.1 for Young’s modulus.)

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Chemistry 131 Week 2 (Sept. 4 - Sept. 8) Chapter 1 - Atoms 1.9 Atomic Mass: The Average Mass of an Element • Atomic mass - average mass of an element ◦ Located under the symbol of each element on the periodic table ◦ Represents average mass of the isotopes that make up each element ◦ Weighted Average Atomic Masses (also amu) - accounts for isotope masses and distributions ‣ Cl-35 and Cl-37 of chlorine are the two most common isotopes • General equation used for atomic mass ◦ Atomic mass unit (amu) = (fraction isotope n) x (mass of isotope n) ◦ = (fraction isotope 1 x mass isotope 1) + (fraction isotope 2 x mass isotope 2) + etc . . . ‣ The sum of isotope mass x the fractional abundance ◦ 1 amu = 1.661 x 10^-27 kg • In broader terms, t

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