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Jeff of the Jungle swings on a vine that is 7.20 m long
Chapter 10, Problem 34P(choose chapter or problem)
Jeff of the Jungle swings on a vine that is 7.20 m long (Figure 10–18). At the bottom of the swing, just before hitting the tree, Jeff’s linear speed is 8.50 m/s.
(a) Find Jeff’s angular speed at this time.
(b) What centripetal acceleration does Jeff experience at the bottom of his swing?
(c) What exerts the force that is responsible for Jeff’s centripetal acceleration?
Equation Transcription:
Text Transcription:
r=7.20 m
v=8.50 m/s
Questions & Answers
QUESTION:
Jeff of the Jungle swings on a vine that is 7.20 m long (Figure 10–18). At the bottom of the swing, just before hitting the tree, Jeff’s linear speed is 8.50 m/s.
(a) Find Jeff’s angular speed at this time.
(b) What centripetal acceleration does Jeff experience at the bottom of his swing?
(c) What exerts the force that is responsible for Jeff’s centripetal acceleration?
Equation Transcription:
Text Transcription:
r=7.20 m
v=8.50 m/s
ANSWER:
Step 1 of 4
a.)
We have to find Jeff's angular speed at the bottom of a swing.
The angular speed at the bottom of the swing can be found using the expression,
Where,
linear speed = 8.50 m/s
radius of the vine = 7.20 m