Problem 89GP

A diver runs horizontally off the end of a diving tower 3.0 m above the surface of the water with an initial speed of 2.6 m/s. During her fall she rotates with an average angular speed of 2.2 rad/s. (a) How many revolutions has she made when she hits the water? (b) How does your answer to part (a) depend on the diver's initial speed? Explain.

Solution 89GP

Part (a)

Step 1 of 4:

A diver runs horizontally with an initial speed and dives from the diving tower with an average angular speed. The height above the surface of the water is given. We are going to find the revolutions made by the diver. Assume that the initial vertical speed (voy) of the diver is zero.

The initial horizontal speed vox = 2.6 m/s

The vertical displacement made by the diver Δy = 3.0 m

The average angular speed of the diver ⍵ave = 2.2 rad/s

The acceleration due to gravity g = 9.81 m/s2