The acronym ANOVA stands for .
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Textbook Solutions for Statistics: Informed Decisions Using Data
Question
Births by Day of Week An obstetrician knew that there were more live births during the week than on weekends. She wanted to determine whether the mean number of births was the same for each of the five days of the week. She randomly selected eight dates for each of the five days of the week and obtained the following data: Monday Tuesday Wednesday Thursday Friday 10,456 11,621 11,084 11,171 11,545 10,023 11,944 11,570 11,745 12,321 10,691 11,045 11,346 12,023 11,749 10,283 12,927 11,875 12,433 12,192 10,265 12,577 12,193 12,132 12,422 11,189 11,753 11,593 11,903 11,627 11,198 12,509 11,216 11,233 11,624 11,465 13,521 11,818 12,543 12,543 Source: National Center for Health Statistics (a) Write the null and alternative hypotheses.(b) State the requirements that must be satisfied to use the onewayANOVA procedure.(c) Use the following MINITAB output to test the hypothesis ofequal means at the a = 0.01 level of significance.One-way ANOVA: Mon, Tues, Wed, Thurs, FriDF43539SourceFactorErrorTotalMS2876908293451SS115076331027078121778414F9.80P0.000(d) Shown are side-by-side boxplots for each weekday. Do theseboxplots support the results obtained in part (c)?WednesdayTuesdayMondayNumber of BirthsDayThursdayFriday10,000 11,000 12,000 13,000
Solution
The first step in solving 13.1 problem number 16 trying to solve the problem we have to refer to the textbook question: Births by Day of Week An obstetrician knew that there were more live births during the week than on weekends. She wanted to determine whether the mean number of births was the same for each of the five days of the week. She randomly selected eight dates for each of the five days of the week and obtained the following data: Monday Tuesday Wednesday Thursday Friday 10,456 11,621 11,084 11,171 11,545 10,023 11,944 11,570 11,745 12,321 10,691 11,045 11,346 12,023 11,749 10,283 12,927 11,875 12,433 12,192 10,265 12,577 12,193 12,132 12,422 11,189 11,753 11,593 11,903 11,627 11,198 12,509 11,216 11,233 11,624 11,465 13,521 11,818 12,543 12,543 Source: National Center for Health Statistics (a) Write the null and alternative hypotheses.(b) State the requirements that must be satisfied to use the onewayANOVA procedure.(c) Use the following MINITAB output to test the hypothesis ofequal means at the a = 0.01 level of significance.One-way ANOVA: Mon, Tues, Wed, Thurs, FriDF43539SourceFactorErrorTotalMS2876908293451SS115076331027078121778414F9.80P0.000(d) Shown are side-by-side boxplots for each weekday. Do theseboxplots support the results obtained in part (c)?WednesdayTuesdayMondayNumber of BirthsDayThursdayFriday10,000 11,000 12,000 13,000
From the textbook chapter Comparing Three or More Means (One-Way Analysis of Variance) you will find a few key concepts needed to solve this.
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