The americium nucleus, decays to a neptunium nucleus, by

Chapter 26, Problem 44

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(III) The americium nucleus, \({ }_{95}^{241} \mathrm{Am}\), decays to a neptunium nucleus, \({ }_{93}^{237} \mathrm{~Np}\), by emitting an alpha particle of mass 4.00260 u and kinetic energy 5.5 MeV.. Estimate the mass of the neptunium nucleus, ignoring its recoil, given that the americium mass is 241.05682 u.

Equation Transcription:

Text Transcription:

{ }_{95}^{241} {Am}

{ }_{93}^{237} {Np}

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