Four stereoisomers exist for 3-penten-2-ol. 3-Penten-2-ol | StudySoup

Textbook Solutions for Organic Chemistry

Chapter 5 Problem 5.24

Question

Four stereoisomers exist for 3-penten-2-ol. 3-Penten-2-ol OH CH39CH"CH9CH9CH3 (a) Explain how these four stereoisomers arise. (b) Draw the stereoisomer having the E confi guration about the carbon-carbon double bond and the R confi guration at the chiral center.

Solution

Problem 5.24

Four stereoisomers exist for 3-penten-2-ol.

(a) Explain how these four stereoisomers arise. (b) Draw the stereoisomer having the E configuration about the carbon-carbon double bond and the R configuration at the chiral center.

        

                                                               Step by Step Solution

Step 1 of 2

a)

The given structure is as follows.

                               

Because of the double - bond with unique substituents in all four bonds there is E, Z configuration. Because there is a chiral carbon with four unique bonds (hydroxyl group, methyl group, hydrogen and carbon chain) there is R, S configuration around that carbon as well.

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Title Organic Chemistry 6 
Author William H. Brown, Christopher S. Foote , Brent L. Iverson, Eric Anslyn
ISBN 9780840054982

Four stereoisomers exist for 3-penten-2-ol. 3-Penten-2-ol

Chapter 5 textbook questions

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