Use the same formula to show that 12,570 joules are | StudySoup

Textbook Solutions for Conceptual Physics

Chapter 15 Problem 34PAC

Question

The quantity of heat Q released or absorbed from a substance of specific heat c (which can be expressed in units \(\mathrm{cal} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}\) or \(\mathrm{J} / \mathrm{kg} \cdot{ }^{\circ} \mathrm{C}\)) and mass m (in g or kg) undergoing a change in temperature \(\Delta T\) is

\(Q=c m \Delta T\)

Use the same formula to show that 12,570 joules are required to raise the temperature of the same mass (0.30 kg) of water through the same temperature interval. For the specific heat capacity c, use \(4190 \quad \mathrm{J} / \mathrm{kg} \cdot{ }^{\circ} \mathrm{C}\).

Text Transcription:

cal / g cdot^circ C

J / kg cdot^circ C

Delta T

Q = cm Delta T

4190 J / kg cdot^circ C

Solution

Step 1 of 2

Given:

Mass of water:

Specific heat capacity:

Initial temperature:

Final temperature:

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full solution

Title Conceptual Physics 12 
Author Paul G. Hewitt
ISBN 9780321909107

Use the same formula to show that 12,570 joules are

Chapter 15 textbook questions

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