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Get Full Access to University Physics - 13 Edition - Chapter 24 - Problem 14e
Get Full Access to University Physics - 13 Edition - Chapter 24 - Problem 14e

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A spherical capacitor is formed from two concentric,

ISBN: 9780321675460 31

Solution for problem 14E Chapter 24

University Physics | 13th Edition

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Problem 14E

A spherical capacitor is formed from two concentric, spherical, conducting shells separated by vacuum. The inner sphere has radius 15.0 cm and the capacitance is 116 pF. (a) What is the radius of the outer sphere? (b) If the potential difference between the two spheres is 220 V, what is the magnitude of charge on each sphere?

Step-by-Step Solution:

Solution 14E Step 1 of 4: A spherical capacitor has capacitance C=116 pF has charge Q under the applied potential difference V= 220 V with the inner radius a=15 cm and outer radius b. Here we need to calculate Part (a)outer radius, b= and the magnitude of charge on each sphere, Q=. Given data, Voltage, V= 220 V 12 Capacitance, C=116 pF =116× 10 m 2 Inner radius, a = 15 cm= 15 × 10 m 9 2 2 Constant k=9 × 10 N.m /C To find, (a) Outer radius, a= (b) The magnitude of charge on each sphere, Q=

Step 2 of 4

Step 3 of 4

ISBN: 9780321675460

Since the solution to 14E from 24 chapter was answered, more than 727 students have viewed the full step-by-step answer. The answer to “A spherical capacitor is formed from two concentric, spherical, conducting shells separated by vacuum. The inner sphere has radius 15.0 cm and the capacitance is 116 pF. (a) What is the radius of the outer sphere? (b) If the potential difference between the two spheres is 220 V, what is the magnitude of charge on each sphere?” is broken down into a number of easy to follow steps, and 57 words. This full solution covers the following key subjects: sphere, spherical, radius, Outer, conducting. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. This textbook survival guide was created for the textbook: University Physics, edition: 13. University Physics was written by and is associated to the ISBN: 9780321675460. The full step-by-step solution to problem: 14E from chapter: 24 was answered by , our top Physics solution expert on 05/06/17, 06:07PM.

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