Solution Found!
A constant potential difference of 12 V is maintained
Chapter 24, Problem 42E(choose chapter or problem)
A constant potential difference of is \(0.25-\mu \mathrm{F}\) maintained between the terminals of a parallel-plate, air capacitor. (a) A sheet of Mylar is inserted between the plates of the capacitor, completely filling the space between the plates. When this is done, how much additional charge flows onto the positive plate of the capacitor (see Table 24.1)? (b) What is the total induced charge on either face of the Mylar sheet? (c) What effect does the Mylar sheet have on the electric field between the plates? Explain how you can reconcile this with the increase in charge on the plates, which acts to increase the electric field.
Questions & Answers
QUESTION:
A constant potential difference of is \(0.25-\mu \mathrm{F}\) maintained between the terminals of a parallel-plate, air capacitor. (a) A sheet of Mylar is inserted between the plates of the capacitor, completely filling the space between the plates. When this is done, how much additional charge flows onto the positive plate of the capacitor (see Table 24.1)? (b) What is the total induced charge on either face of the Mylar sheet? (c) What effect does the Mylar sheet have on the electric field between the plates? Explain how you can reconcile this with the increase in charge on the plates, which acts to increase the electric field.
ANSWER:Solution 42E We need to first calculate the charge of the plates when the space between them is filled with air. Then we need to do the same calculation when the space is filled with the mylar sheet. Then, we shall calculate the additional charge flowing onto the positive plate of the capacitor. Given, potential difference PD = 12.0 V Capacitance C = 0.25 F = 0.25 × 10 6F Therefore, charge Q = PD × C Q = 12.0V × 0.25 × 10 6 F = 3.0 × 10 6 C Q = 3.0 C The d