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Get Full Access to University Physics - 13 Edition - Chapter 24 - Problem 18e
Get Full Access to University Physics - 13 Edition - Chapter 24 - Problem 18e

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# In Fig. 24.8a, let

ISBN: 9780321675460 31

## Solution for problem 18E Chapter 24

University Physics | 13th Edition

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University Physics | 13th Edition

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Problem 18E

In Fig. 24.8a, let

Step-by-Step Solution:

Solution 18E Step 1 of 5: Given 6 C 1 3 × 10 F C = 5 × 10 F 6 2 5 Q = 9.75 × 10 C V = 1 V 2 First we have to find the effective capacitance of the capacitors,then the charge and finally potential difference across the C a1d C . 2 When the two capacitors are in series , then the equivalent capacitance ! = ! + ! = ! + 1 = 5.33 × 10 F 1 Ceq C1 C2 3×10 F 5×10 F C eq = 15 1 = 1.88 × 10 F6 5.33×10 F

Step 2 of 5

Step 3 of 5

##### ISBN: 9780321675460

University Physics was written by and is associated to the ISBN: 9780321675460. Since the solution to 18E from 24 chapter was answered, more than 289 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 18E from chapter: 24 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. This textbook survival guide was created for the textbook: University Physics, edition: 13. This full solution covers the following key subjects: fig, let. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. The answer to “In Fig. 24.8a, let” is broken down into a number of easy to follow steps, and 4 words.

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