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Solved: Critical points Find the critical points of the

Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett ISBN: 9780321570567 2

Solution for problem 9RE Chapter 4

Calculus: Early Transcendentals | 1st Edition

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Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

Calculus: Early Transcendentals | 1st Edition

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Problem 9RE

Critical points Find the critical points of the following functions on the given intervals. Identify the absolute minimum and absolute maximum values (if possible). Graph the function to confirm your conclusions. f(x) = 2x ln x +10on [0,4]

Step-by-Step Solution:

Solution 9RE Step 1 In this problem we have to find the critical points of the function f(x) = 2x ln x +10and also we have to identify absolute maximum and absolute minimum. First let us see the definitions of critical point, absolute maximum,absolute minimum. Critical point: n interior point cof the domain of a function f at which f (c) = 0or f (c) fails to exist is called a critical point of f Absolute maximum: The highest point over the entire domain of a function or relation is the absolute maximum. Absolute minimum: The lowest point over the entire domain of a function or relation is the absolute minimum. Step 2 Given f(x) = 2x ln x +10 on [0,4] Since f(x) is a polynomial, its derivative exists everywhere. By the definition of critical points, If f has critical points they are points at which f (x) = 0. Here f (x) = 2(ln x + x )+x f (x) = 2(ln x + 1) Now f (x) = 0 2(ln x +1) = 0 ln x+1 = 0 ln x = 1 Raising to the power e on both sides we get, x = e (Since ln and ecancel each other) 1 x = e Step 3 Thus the critical point is x = 1 which lie in the interval [0,4]. e This critical point and the end points help us to locate the absolute extrema. Now let us find the value of f(x)at these points. At x = 0, f(0) = 2(0) ln 0+10 = 10 1 1 1 1 At x = ,ef( )e= 2( ) le ( )+1e = 9.2642 At x = 4, f(4) = 2(4) ln 4+10 = 21.0904

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Chapter 4, Problem 9RE is Solved
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Textbook: Calculus: Early Transcendentals
Edition: 1
Author: William L. Briggs, Lyle Cochran, Bernard Gillett
ISBN: 9780321570567

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