Problem 29SP Show how you would make the following ethers, using only simple alcohols and any needed reagents as your starting materials. (a) 1-methoxybutane (b) 2-ethoxy-2-methylpropane (c) benzyl cyclopentyl ether (d) trans-2-methoxycyclohexanol (e) the TIPS ether of (d) (f) cyclohexyl cyclopentyl ether
Read moreTable of Contents
1
Introduction and Review
2
Carbohydrates and Nucleic Acids
3
The Study of Chemical Reactions
4
Stereochemistry
5
Alkyl Halides: Nucleophilic Substitution and Elimination
6
Reactions of Alkenes
8
Amines
9
Carboxylic Acid Derivatives
10
Structure and Properties of Organic Molecules
11
Structure and Stereochemistry of Alkenes
12
Carboxylic Acids
13
Ketones and Aldehydes
14
Amino Acids, Peptides, and Proteins
15
Alkynes
16
Structure and Synthesis of Alcohols
17
Reactions of Alcohols
18
Infrared Spectroscopy and Mass Spectrometry
19
Nuclear Magnetic Resonance Spectroscopy
20
Ethers, Epoxides, and Thioethers
21
Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy
22
Aromatic Compounds
23
Reactions of Aromatic Compounds
24
Lipids
25
Synthetic Polymers
26
Condensations and Alpha Substitutions of Carbonyl Compouds
Textbook Solutions for Organic Chemistry
Chapter 14 Problem 32SP
Question
Give IUPAC names for the following compounds.
(a) \(\mathrm{CH}_{3} \mathrm{OCH}\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{2} \mathrm{OH}\)
(b) \(\mathrm{PhOCH}_{2} \mathrm{CH}_{3}\)
Solution
Step 1 of 4
(a)The first compound has a three-carbon long parent chain having the alcohol function group and methoxy substituent at the second carbon; therefore, its IUPAC name is 2-methoxypropan-1-ol.
(b)The first compound has a six-carbon long aromatic parent chain with the ethoxy substituent at the first carbon; its IUPAC name becomes ethoxybenzene.
(c)The third compound has a five-carbonlong cyclic parent chain having methoxy substituent at the first carbon; therefore, its IUPAC name ismethoxycyclopentane.
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Title
Organic Chemistry 8
Author
L.G. Wade Jr
ISBN
9780321768414