Answer: In putting, the force with which a golfer strikes
Chapter 25, Problem 67GP(choose chapter or problem)
In putting, the force with which a golfer strikes a ball is planned so that the ball will stop within some small distance of the cup, say, 1.0 m long or short, in case the putt is missed. Accomplishing this from an uphill lie (that is, putting downhill, see Fig. 2–39) is more difficult than from a downhill lie. To see why, assume that on a particular green the ball decelerates constantly at \(2.0 \mathrm{~m} / \mathrm{s}^{2}\) going downhill, and constantly at
\(3.0 \mathrm{~m} / \mathrm{s}^{2}\) going uphill. Suppose we have an uphill lie 7.0 m from the cup. Calculate the allowable range of initial velocities we may impart to the ball so that it stops in the range 1.0 m short to 1.0 m long of the cup. Do the same for a downhill lie 7.0 m from the cup. What in your results suggests that the downhill putt is more difficult?
Equation Transcription:
Text Transcription:
2.0 m/s2
3.0 m/s2
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