Calculate the displacement and velocity at times of (a) 0.500, (b) 1.00, (c) 1.50, (d) 2.00, and (e) 2.50 s for a rock thrown straight down with an initial velocity of 14.0 m/s from the Verrazano Narrows Bridge in New York City. The roadway of this bridge is 70.0 m above the water.

Step-by-step solution Step 1 of 6 The displacement of the rock from its initial position is, The final velocity of the rock is, Here, a is the acceleration of the rock, t is time for which rock acc elerates and u is the initial velocity of rock. Step 2 of 6 (a) The displacement of the rock from its initial position after 0.500 s is, The velocity of the rock after 0.500 s is, Substitute for u , for and 0.500 s for t . Hence, the displacement and the velocity of the rock are and respectively. Step 3 of 6 (b) The displacement of the rock from its initial position after 1.00 s is, Su bstitute for u , for a and 1.00 s for t. The velocity of the rock after 1.00 s is, Substitute for u, for a and 1.00 s for t. Hence, the displacement and the velocity of the rock are and respectively.