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Get Full Access to University Physics - 13 Edition - Chapter 1 - Problem 92p
Get Full Access to University Physics - 13 Edition - Chapter 1 - Problem 92p

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# Vector has magnitude 6.00 m and vector has magnitude 3.00 ISBN: 9780321675460 31

## Solution for problem 92P Chapter 1

University Physics | 13th Edition

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Problem 92P

Vector has magnitude 6.00 m and vector has magnitude 3.00 m. the vector product between these two vectors has magnitude 12.0 m2. What are the two possible values for the scalar product of these two vectors? for each value of , draw a sketch that shows and and explain why the vector products in the two sketches are the same but the scalar products differ.

Step-by-Step Solution:

Solution 92P Step 1: Provided magnitude of vector A = 6 m Magnitude of vector B = 3 m Then their vector product would be, A × B = AB sin Provided, A × B = 12 m2 2 Therefore, 12 m = 6m × 3m × sin 2 2 sin = 12 m / 18 m sin = 2/ 3

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Step 3 of 5

##### ISBN: 9780321675460

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