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Vector has magnitude 6.00 m and vector has magnitude 3.00

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 92P Chapter 1

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 92P

Vector has magnitude 6.00 m and vector has magnitude 3.00 m. the vector product between these two vectors has magnitude 12.0 m2. What are the two possible values for the scalar product of these two vectors? for each value of , draw a sketch that shows and and explain why the vector products in the two sketches are the same but the scalar products differ.

Step-by-Step Solution:

Solution 92P Step 1: Provided magnitude of vector A = 6 m Magnitude of vector B = 3 m Then their vector product would be, A × B = AB sin Provided, A × B = 12 m2 2 Therefore, 12 m = 6m × 3m × sin 2 2 sin = 12 m / 18 m sin = 2/ 3

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Chapter 1, Problem 92P is Solved
Step 3 of 5

Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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Vector has magnitude 6.00 m and vector has magnitude 3.00