Solved: A proton is suspended at rest in a uniform

Chapter 16, Problem 60GP

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A proton \(\left(m=1.67 \times 10^{-27} \mathrm{~kg}\right)\)  is suspended at rest in a uniform electric field \(\(\vec{E}\)\). Take into account gravity at the Earth's surface, and determine \(\vec{E}\).

Equation transcription:

Text transcription:

(m=1.67 times 10^{-27}{~kg})

vec{E}