Solved: An electron with speed is traveling parallel to an
Chapter 16, Problem 62GP(choose chapter or problem)
An electron with speed \(v_{0}=5.32 x 10^{6} m / s\) is traveling parallel to an electric field of magnitude \(E=9.45 \times 10^{3} N / C\). (a) How far will the electron travel before it stops? (b) How much time will elapse before it returns to its starting point?
Equation transcription:
Text transcription:
v{0}=5.32 x 10^{6} m / s
E=9.45 times 10^{3} N / C
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