During the time 0.305 mol of an ideal gas undergoes an | StudySoup

Textbook Solutions for University Physics

Chapter 19 Problem 5E

Question

During the time 0.305 mol of an ideal gas undergoes an isothermal compression at 22.0°C. 468 J of work is done on it by the surroundings. (a) If the final pressure is 1.76 atm, what was the initial pressure? (b) Sketch a ?pV?-diagram for the process.

Solution

Solution 5E Step 1: We need to find the initial pressure and also sketch PV diagram of the process Data given Temperature T = 22 C + 273 = 295K Work done W = 468 J Final pressure P = f.76 atm n = 0.305 mol This can be obtained using W = nRT Pi Pf Since we need to final initial pressure,we shall rearrange the equation We get w P i P × ef nRT Substituting the values we get 468 J P i 1.76 atm × e 0.305 mol×8.3144×295K P i 1.76 atm × e 0.6255 P i 1.76 atm × 0.5347 P = 0.941 atm i Hence we have initial pressure as 0.941 atm

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full solution

Title University Physics 13 
Author Hugh D. Young, Roger A. Freedman
ISBN 9780321675460

During the time 0.305 mol of an ideal gas undergoes an

Chapter 19 textbook questions

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