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During the time 0.305 mol of an ideal gas undergoes an
Chapter 19, Problem 5E(choose chapter or problem)
During the time 0.305 mol of an ideal gas undergoes an isothermal compression at 22.0°C. 468 J of work is done on it by the surroundings. (a) If the final pressure is 1.76 atm, what was the initial pressure? (b) Sketch a ?pV?-diagram for the process.
Questions & Answers
QUESTION:
During the time 0.305 mol of an ideal gas undergoes an isothermal compression at 22.0°C. 468 J of work is done on it by the surroundings. (a) If the final pressure is 1.76 atm, what was the initial pressure? (b) Sketch a ?pV?-diagram for the process.
ANSWER:Solution 5E Step 1: We need to find the initial pressure and also sketch PV diagram of the process Data given Temperature T = 22 C + 273 = 295K Work done W = 468 J Final pressure P = f.76 atm n = 0.305 mol This can be obtained using W = nRT Pi Pf Since we need to final initial pressure,we shall rearrange the equation We get w P i P × ef nRT Substituting the values we get 468 J P i 1.76 atm × e 0.305 mol×8.3144×295K P i 1.76 atm × e 0.6255 P i 1.76 atm × 0.5347 P = 0.941 atm i Hence we have initial pressure as 0.941 atm