An ideal gas is taken from a to b on the pV-diagram shown in ?Fig. E19.15?. During this process, 700 J of heat is added and the pressure doubles. (a) How much work is done by or on the gas? Explain. (b) How does the temperature of the gas at a com-pare to its temperature at b? Be specific. (c) How does the internal energy of the gas at a compare to the internal energy at b? Be specific and explain.

Solution 15E We know from the 1st law of thermodynamics, dE = dQ dW -----------------(1) Where dE is the change in internal energy. dQ is the heat added to the system. dW is the work done on or by the system. a) So, let’s rewrite equation (1) in a more convenient form, dE = dQ PdV ------------------(2) But the volume has kept constant here. So, dV = 0. dE = dQ--------------------(3) Which means all the heat added to the system contributed to the change in internal energy. Hence no work is done. The work done is zero. b) This is an ideal gas, so we can use the ideal gas...