Comparing Thermodynamic Processes. In a cylinder, 1.20 mol | StudySoup

Textbook Solutions for University Physics

Chapter 19 Problem 68P

Question

Comparing Thermodynamic Processes. In a cylinder, 1.20 mol of an ideal monatomic gas, initially at 3.60 X 105 Pa and 300 K, expands until its volume triples. Compute the work done by the gas if the expansion is (a) isothermal; (b) adiabatic; (c) isobaric. (d) Show each process in a pV-diagram. In which case is the absolute value of the work done by the gas greatest? Least? (e) In which case is the absolute value of the heat transfer greatest? Least? (f) In which case is the absolute value of the change in internal energy of the gas greatest? Least?

Solution

Solution 68P a.) An isothermal process is a constant-temperature process. Step 1 of 2: Work done by an ideal monatomic gas in expanding isothermally from a volume of (V) to three times its volume(3V) initially at a pressure of 3.6 × 10 5 Pa and temperature of 300k can be computed as vf W = P × dV vi = n × R × T ×ln V [/V i ] = 1.20× 8.31 × 300 ×ln 3V[/V ] = 1.20 × 8.31 × 300 × ln 3 [ ] = 1.20× 8.31 × 300 × 1.098 W = 3286.6 J

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full solution

Title University Physics 13 
Author Hugh D. Young, Roger A. Freedman
ISBN 9780321675460

Comparing Thermodynamic Processes. In a cylinder, 1.20 mol

Chapter 19 textbook questions

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