The process ?abc shown in the ?pV?-diagram in ?Fig. E19.11 involves 0.0175 mol of an ideal gas. (a) What was the lowest temperature the gas reached in this process? Where did it occur? (b) How much work was done by or on the gas from ?a to ?b?? From ?b to ?c?? (c) If 215 J of heat was put into the gas during ?abc?, how many of those joules went into internal energy?
Solution 11E Step 1 of 3: pV nRT = determines the Kelvin temperature of the gas. The work done in the process is the area under the curve in the pV diagram. Q is positive since heat goes into the gas 1 L = 1 × 10 m3 3 paVa Ta= nR 5 3 3 = 0.2 atm×1.013×10pa/atm ×2 L×1×10 m L 0.0175 mol×8.325 j/ mol.K = 278 K