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Boiling Water at High Pressure. When water is boiled at a
Chapter 19, Problem 14E(choose chapter or problem)
Boiling Water at High Pressure. When water is boiled at a pressure of 2.00 atm, the heat of vaporization is 2.20 X 106 J/kg and the boiling point is 120o C. At this pressure, 1.00 kg of water has a volume of 1.00 X 10-3 m3, and 1.00 kg of steam has a volume of 0.824 m3. (a) Compute the work done when 1.00 kg of steam is formed at this temperature. (b) Compute the increase in internal energy of the water.
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QUESTION:
Boiling Water at High Pressure. When water is boiled at a pressure of 2.00 atm, the heat of vaporization is 2.20 X 106 J/kg and the boiling point is 120o C. At this pressure, 1.00 kg of water has a volume of 1.00 X 10-3 m3, and 1.00 kg of steam has a volume of 0.824 m3. (a) Compute the work done when 1.00 kg of steam is formed at this temperature. (b) Compute the increase in internal energy of the water.
ANSWER:Solution 14E Step 1: 5 The pressure is 2 atm = 2.026 × 10 Pa. The temperature has kept constant. So, when the water of 1 kg changes it’s phase to 1 kg of vapour, The work done is defined as, V f W = PdV V i As the pressure is constant, the work done will be, W = pressure × (final volume initial volume) 5 3 = 2.026 × 10 Pa × (0.824 1 × 10 ) 5 5 = 2.026 × 10 × 0.823 = 1.667 × 10 jules So, this much work will be done. b)