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CALC The temperature of 0.150 mol of an ideal gas is held

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 27E Chapter 19

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 27E

CALC The temperature of 0.150 mol of an ideal gas is held constant at 77.0o C while its volume is reduced to 25.0% of its initial volume. The initial pressure of the gas is 1.25 atm. (a) Determine the work done by the gas. (b) What is the change in its internal energy? (c) Does the gas exchange heat with its surroundings? If so, how much? Does the gas absorb or liberate heat?

Step-by-Step Solution:

Solution 27E Step 1 of 5: 0 In the given process, temperature remains constant at T=77 c. Since an isothermal process is a constant-temperature process. For a process to be isothermal, any heat flow into or out of the system must occur slowly enough that thermal equilibrium is maintained. Step 2 of 5: (b) What is the change in its internal energy In general; in case of isothermal, none of the quantities like change in internal energy( U ), work done(W) and energy supplied (Q) is zero.But in some special cases like ideal gas,where the internal energy of a system depends only on its temperature, not on its pressure or volume. For such systems like ideal gas, if the temperature is constant, the internal energy is also constant; and That is, any energy entering the system as heat Q must leave it again as work W done by the system. Hence U = 0 W= Q Therefore, change in internal energy is zero in the given case. Step 3 of 5: (a) Determine the work done by the gas. Given data, Number of moles, n=0.150 mol Gas constant , R= 8.314 J/mol.K Temperature, T = T = T = 77 c 0 1 2 Using T = T + c73.15 T = 77 + 273.15 K T = 350.15 K Initial volume, V = V 1 Final volume, V =20.25 V To find, Work done, W=

Step 4 of 5

Chapter 19, Problem 27E is Solved
Step 5 of 5

Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

Since the solution to 27E from 19 chapter was answered, more than 248 students have viewed the full step-by-step answer. The answer to “CALC The temperature of 0.150 mol of an ideal gas is held constant at 77.0o C while its volume is reduced to 25.0% of its initial volume. The initial pressure of the gas is 1.25 atm. (a) Determine the work done by the gas. (b) What is the change in its internal energy? (c) Does the gas exchange heat with its surroundings? If so, how much? Does the gas absorb or liberate heat?” is broken down into a number of easy to follow steps, and 73 words. University Physics was written by and is associated to the ISBN: 9780321675460. This textbook survival guide was created for the textbook: University Physics, edition: 13. The full step-by-step solution to problem: 27E from chapter: 19 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. This full solution covers the following key subjects: gas, its, Volume, heat, initial. This expansive textbook survival guide covers 26 chapters, and 2929 solutions.

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