How far out on the diving board (Fig. 9–42) would a 58-kg diver have to be to exert a torque of 1100m · N on the board, relative to the left (A) support post?

FIGURE 9–42

Solution 4P Step 1 of 3 The area unde r the -t graph will gives the impulse produced. From the figure, the graph represents a triangle. So, the area under the graph is, J= Area under the graph J= (base)(height) 2 Here, J is the impulse. Step 2 of 3 In the graph time axis represents the base and force axis represents the height. Therefore, base is given by, Base=(8ms-0ms) Height is given by, Height=(F max-0)