(a) Nitrogen has relatively stable isotopes (half-life greater than 1 second) of mass numbers 13, 14, 15, 16, and 17. (All except 14N and 15N are radioactive.) Calculate how many protons and neutrons are in each of these isotopes of nitrogen. (b) Write the electronic configurations of the third-row elements shown in the partial periodic table in Figure 1-6.
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Textbook Solutions for Organic Chemistry
Question
Write Lewis structures for the following molecular formulas.
(a) \(\mathrm{N}_{2}\)
(b) \(\rm{HCN}\)
(c) \(\rm{HONO}\)
(d) \(\rm{CO}_2\)
(e) \(\mathrm{CH}_{3} \mathrm{CHNH}\)
(f) \(\mathrm{HCO}_{2} \mathrm{H}\)
(g) \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Cl}\)
(h) \(\rm{HNNH}\)
(i) \(\mathrm{C}_{3} \mathrm{H}_{6}\) (one double bond)
(j) \(\mathrm{C}_{3} \mathrm{H}_{4}\) (two double bonds)
(k) \(\mathrm{C}_{3} \mathrm{H}_{4}\) (one triple bond)
Solution
Step 1 of 11
Lewis structure:
Structure of a molecule in which bonding between the atoms and of lone pairs of electrons shown is called Lewis structure.
The procedure to draw the Lewis structure of the molecule is as follows:
- Sum the valence electrons from all the atoms in a molecule
- Connect all the atoms with a single bond.
- Complete the octet around all the atoms bonded to the central atom.
- Place leftover electrons on the central atom
- Try multiple bonds, if there are not enough electrons to give the central atom an octet.
a) The given molecule - \(N_{2}\)
* Calculating the total number of valence electrons in \(N_{2}\) is as follows.
Each nitrogen atom has five valence electrons.
\(\text { Valence electrons in } N_{2}=2 \times 5=10\)
* Draw the skeletal structure of \(N_{2}\) as follows.
To make a bond between these two nitrogen atoms requires two electrons, so remaining valence electrons are 8.
Complete the octet for nitrogen atoms by replacing four valence electrons as bond pairs between two nitrogen atoms and the remaining four as lone pairs on nitrogen atoms.
Therefore, the Lewis structure of \(N_{2}\) is as follows.
full solution